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frosja888 [35]
3 years ago
11

Can someone help me please?​

Mathematics
1 answer:
jeka57 [31]3 years ago
7 0

Answer:

85

Step-by-step explanation:

because A is half of that and if you divided 170 by 2 you would get 85, I think that's how you do it.

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Help help help help help help help help help help help help help help help help help help​
kvv77 [185]

Answer:

Step-by-step explanation:

Part 1

P(z < -1.45)

Using the z score table

P =

Part 2

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) P(X >52)

x = 52

Mean = 60

Standard deviation = 8

z = 52 - 60/8

z = -1

P-value from Z-Table:

P(x<52) = 0.15866

P(x>52) = 1 - P(x<52) = 0.84134

b) P(48 < x < 64)

5 0
2 years ago
PLEASE HELP ME!!!!
Contact [7]
The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)


find slope

slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5


pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2

y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
5 0
3 years ago
To convert 8.5 yards to feet which ratio could you multiply by
uranmaximum [27]
8.5 yd/1 * 3ft/1yd ................
7 0
2 years ago
Read 2 more answers
What is the area of the trapezoid
irga5000 [103]

The equation for a trapezoid is A = a+b all over 2 times h

So, you would simply substitute.

A=15

B=12

H=8

15+12/2 (8)=

27/2 (8)=

13.5 (8)=

108.

6 0
3 years ago
Read 2 more answers
What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

6 0
3 years ago
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