Answer:
A= -1, B = -8, C = -6
Step-by-step explanation:
Ok so pete lays 10 more than jim per hour
pete and jim laid same amount of tiles
j=jim's rate
p=pete's rate
6j=5p
but pete lays 10 tile per hour faster so
p=10+j
sub
6j=5(10+j)
6j=50+5j
minus 5j both sides
j=50
jim can lay at 50 tiles per hour
Answer:
The mentioned number in the exercise is:
Step-by-step explanation:
To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.
If:
- x = hundredths digit
- y = tens digit
- z = ones digit
We can write:
- x = z + 1 (the hundreds digit is one more than the ones digit).
- y = 2x (the tens digit is twice the hundreds digit).
- x + y + z = 11 (the sum of the digits is 11).
Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:
- x + y + z = 11
- (z + 1) + y + z = 11 (remember x = z + 1)
- z + 1 + y + z = 11
- z + z +y + 1 = 11 (we just ordered the equation)
- 2z + y + 1 = 11 (z + z = 2z)
- 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
- 2z + y = 10
- 2z + (2x) = 10 (remember y = 2x)
- 2z + 2x = 10
- 2z + 2(z + 1) = 10 (x = z + 1 again)
- 2z + 2z + 2 = 10
- 4z + 2 = 10
- 4z = 10 - 2
- 4z = 8
- z = 8/4
- <u>z = 2</u>
Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:
- x = z + 1
- x = 2 + 1
- <u>x = 3</u>
And we'll use the second equation to obtain the value of y (the tens digit):
- y = 2x
- y = 2(3)
- <u>y = 6</u>
Organizing the digits, we obtain the number:
- Number = xyz
- <u>Number = 362</u>
As you can see, <em><u>the obtained number is 362</u></em>.
Answer:
(g · f)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x² - 4x- 5
(g · f)(x) = 4(x² - 5) + 1
(g · f)(4) = 4(4² - 5) + 1
Following pemdas
(g · f)(4) = 4(16 - 5) + 1
(g · f)(4) = 4(11) + 1
(g · f)(4) = 44 + 1
(g · f)(4) = 45
