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maxonik [38]
3 years ago
10

Given the zeros of the function f (x) = x4 + 3x3 – 28x², identify whether the zero is a bounce or

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0
Assuming the function is

f(x) = x^4 + 3x^3-28x^2

Factorising, we get

f(x) = x^2(x+7)(x-4)

Therefore, there is a double root at x = 0 and singular roots at x = -7 and 4

double roots tend to bounce, kind of like the standard quadratic y = x^2

singular roots tend to cross, kind of like a straight line on a graph, y = mx + b

Therefore, it bounces at x = 0, and crosses at x = -7 and 4

In general, a root raised to an even power bounces, and a root raised to an odd power crosses.
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What is the solution to the system of equations?
o-na [289]

Answer:

x = -5

y = 4

Step-by-step explanation:

3x + 4y = 1    /*(-4)

4x + 5y = 0   /*3

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-12x - 16y = -4

12x + 15y = 0     +

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-y = -4

y = 4

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12x = -15y

12x = -60

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7 0
3 years ago
Read 2 more answers
Kate took out a subsidized Stafford loan worth $9,710 to pay for college.  The interest rate on the loan was 5.9%, compounded mo
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<span>If Kate took out a loan of $9,710 and it took her 5 years to pay off she would have to pay 60 months of interest. Given that, the interest rate of 5.9% would of been $572.89 the first month. Use this information to find the answer. 

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3 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
4 years ago
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The first equation can be simplified down to 3 and -\frac{3}{2}[/tex]. Therefore, ">" is correct.

The second equation can be simplified down to 12 and 6.25. Therefore, "<" is incorrect. It should be ">".

5 0
3 years ago
75,575 how do the values of the digit differ in the number?
Vsevolod [243]

Answer:

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75,57<u>5</u> - ones place; this 5 is worth 5



8 0
3 years ago
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