Question

Can someone answer this question for me quick please I’m struggling :(

Answer 1

Answer:

The correct option is;

CGB

Whereby, we have;

Triangle RKB ~ Triangle CGB

Step-by-step explanation:

The given triangles have the following congruent angles;

Angle ∠RKB on triangle ΔRKB is congruent to angle ∠CGB on triangle ΔCGB

We are given angle ∠KBR on triangle ΔRKB is congruent to angle ∠GBC on triangle ΔCGB

Therefore,  ΔRKB is similar to ΔCGB by the Angle-Angle (AA) rule for similarity.