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Sergeu [11.5K]
2 years ago
9

B. What percent is 17 out of 40? ​

Mathematics
2 answers:
vodomira [7]2 years ago
7 0

Answer:42.5

Step-by-step explanation:

Alex_Xolod [135]2 years ago
5 0

Answer:

42.5%

Step-by-step explanation:

This can be written as 17/40 and when you multiply the numerator and denominator by 2.5, you get 42.5/100 which is 42.5%.

Hope this helps!

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Can someone help me solve this? Pls and ty!
Zanzabum

Answer:

H. 95°

Step-by-step explanation:

m∠BGC is 10° smaller than m∠CGD, which means that m∠BGC is x° - 10°

m∠DGE is 25° more than m∠EGF, which means that m∠DGE is x° + 25°

The sum of all angles in a placement like this will always equal 360°

So we put all the measures of all angles on one side of thee equation and set it equal to 360*

x° + x° - 10° + 2x° + 25° + 2x° + 3x° + 30° = 360°

After combining like terms we get 9x° + 45° = 360°

After some algebra we get x = 35°

Now at the start we said that m∠DGE is x + 25°

Plug in 35° for x and we get 35° + 25°

The final answer is m∠DGE = 95°

Edit: Sorry if my answer looks a bit confusing. This is actually my first answer on Brainly so I'm quite new to this experience.

5 0
2 years ago
Read 2 more answers
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

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Answer:

Is there supposed to be an image?

Step-by-step explanation:

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The slope is 1/2.
You can figure it out using the rise over run method
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In need help step by step
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