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Blababa [14]
3 years ago
6

A gardener is planting two types of trees. Type A is three feet tall and grows at a rate of of 15 inches or year. Type B is four

feet tall and grows at a rate of 10 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0
In between the first year
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C) Similar-SAS

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Which table represents y as a function of x?​
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64 = 4(p + 2) + 24 please solve step by step
Wittaler [7]

Answer:

8

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   1 • -16 = -16

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   6 .

     -16    +    1    =    -15

     -8    +    2    =    -6

     -4    +    4    =    0

     -2    +    8    =    6    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  8

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Step-4 : Add up the first 2 terms, pulling out like factors :

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             Add up the last 2 terms, pulling out common factors :

                   8 • (p-2)

Step-5 : Add up the four terms of step 4 :

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If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
3 years ago
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