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2 years ago

Solve the following 2x=9

Mathematics

2 answers:

jolli1 [7]2 years ago

4 0

The answer is

=9/2

Hope this helps :)

11Alexandr11 [23.1K]2 years ago

4 0

Let's solve your equation step-by-step.

2x=9

Step 1: Divide both sides by 2.

$\frac{2x}{2} =\frac{9}{2} \\Answer: x=\frac{9}{2} \\$

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The density d kg/m3 of a cube of mass m kilograms and side length x meters is given by the formula: What is the value of d if

bearhunter [10]

Answer:

5000kg/m3

Step-by-step explanation:

Its easy to get the answer of a question from the unit.

So, it will be mass over metre cube.

Therefore, m=40kg x= (0. 2)^3 =0. 008m

40/0. 008 = 5000kg/m^3

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3 years ago

The floor of the restaurant is a square of sides 28m. The floor is covered with square tiles of sides 40m. Calculate the total n

lisov135 [29]

Answer:

196000 tiles.

Step-by-step explanation:

The 28 m is 2800 cm. So a 28 x 28 meter square would be 2800 x 2800 centimeter square.

The tiles are 40 cm.

If you divide 40 from (2800 x 2800). (2800 x 2800) ÷40 = 196000

So 196000 tiles.

I'm not entirely sure if that's correct, but if it helps that's awesome.

4 0

3 years ago

Helpppppp show your work

Veronika [31]

(-3²)-2(-3-4)-(-1³)

=9-2(-7)+1

=9+14+1

=24

<em>Hope it helps!</em>

6 0

2 years ago

Read 2 more answers

(3.2 x 8.1) + (3.2 x 1.9)=<br> x<br> (8.1 + 1.9)

marin [14]

Answer:

oh god i uh-

Step-by-step explanation:

7 0

3 years ago

A waste management company is designing a rectangular construction dumpster that will be twice as long as it is wide and must ho

photoshop1234 [79]

Answer:

The dimensions that minimize the surface are:

Wide: 1.65 yd

Long: 3.30 yd

Height: 2.20 yd

Step-by-step explanation:

We have a rectangular base, that its twice as long as it is wide.

It must hold 12 yd^3 of debris.

We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).

The surface is equal to:

$S=2(w*h+w*2w+2wh)=2(3wh+2w^2)$

The volume restriction is:

$V=w*2w*h=2w^2h=12\\\\h=\frac{6}{w^2}$

If we replace h in the surface equation, we have:

$S=2(3wh+2w^2)=6w(\frac{6}{w^2})+4w^2=36w^{-1}+4w^2$

To optimize, we derive and equal to zero:

$dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65$

Then, the height h is:

$h=6/w^2=6/(1.65^2)=6/2.7225=2.2$

The dimensions that minimize the surface are:

Wide: 1.65 yd

Long: 3.30 yd

Height: 2.20 yd

8 0

4 years ago