The temperature at 6.00 am was - 12 the temperature increased by 1/2 each hour for 6 hours what was the temperature in degrees F
1 answer:
Answer: -9 degrees Fahrenheit
Step-by-step explanation:
Given: Temperature at 6:00 AM = -12 degrees Fahrenheit
Temperature increased each hour = degrees Fahrenheit
Temperature increase in 6 hours =
Temperature at noon = Temperature at 6:00 AM+Temperature increase in 6 hours
= -12+3 degrees Fahrenheit
= -9 degrees Fahrenheit
Hence, the temperature in degrees Fahrenheit at noon= -9 degrees Fahrenheit
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<h2>Step-by-step explanation:</h2>
Interest, is an additional money paid for borrowing money. it could be simple or compound interest.
simple interest= p×T×R/100
when interest is compounded annually
F= p(1+r)^t
F= future value
p= principal
r= rate
t= time
compound interest is calculated based on the initial and accumulated interest.
<h2>interest Linda earns</h2><h3>fist year</h3>F= p(n+r)^n
F= 10000(1+0.02)^1
F= 10000×1.02= $10200
interest= 10200-10000
interest = $200
second year
F = 10200(1+0.02)^1
F=10200×1.02= $10404
Interest= 10404-10200
interest= $204
third year
F= 10404(1+0.02)^1
F= 10404(1.02)
F = $10612.08
interest= 10612.08-10404
interest= $208.08
<h2>Bob's interest</h2><h2>I= p×t×R/100</h2>first year
I=10000×1×0.02/100
interest= $2
second year
I= 10000×2×0.02/100
interest= $4
for the third year
I =10000×3 × 0.02/100
interest= $6
<h2>check answer above for final computation</h2>