Answer:
17550 solutions
Step-by-step explanation:
Given that:
y1 +y2+y3+y4=27
where;
(yi ≥ 0 and yi
)
The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.
i.e

∴
The number of nonnegative integer solution is 





= 17550 solutions
Total outcomes=6 i.e{1,2,3,4,5,6 }
No.of favourable outcomes = 3 i.e {I, 3,5}
P(odd)=3/6=1/2