For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down
16 + (-8) = 8 <== here is one
16 - 8 = 8
8 = 8 (correct)
-12 + 20 = 8 <== and another
11 + (- 3) = 8 <== and another
