I could only do b
3(2x + 4) = 2+6x+10
6x+12 = 2+6x+10
6x- 6x = 2+10-12
0x/0 = 0/0
x = 0
I think
We could use the Pythagorean theorem for this kind of problem I think:
A^2 + B^2 = C^2
6^2 + 16^2 = C^2
36 + 256 = C^2
292 = C^2
17.08 = C
C = 17.1 to the nearest tenth
Sorry if it’s wrong and glad I could help if it’s right ❤️❤️ Take care!
For every polynomial function (such as quadratic functions for example), the domain is all real numbers. if the parabola is opening upwards, i.e. a > 0 , the range is y ≥ k ; if the parabola is opening downwards, i.e. a < 0 , the range is y ≤ k .
Answer:
X ~ N(27, 4) ;
xbar ~ N(27, 0.1026) ;
0.5 ;
0.5
Step-by-step explanation:
Probability distribution of X : N(μ, σ²)
μ = 27 ; σ = 2
X ~ N(μ, σ²) = X ~ N(27, 2²) ;X ~ N(27, 4)
Distribution is approximately normal ; μ = xbar ; xbar = 27
(Standard Error)² = (σ/√n)²= (2/√39)² = 0.1026
xbar ~ N(μ, σ²) = xbar ~ N(27, 2²) ; xbar ~ N(27, 0.1026)
Probability that a randomly selected individual found a job in less than 27 weeks :
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ
Z = (27 - 27) / 2 = 0/2
Z = 0
P(Z < 0) = 0.5
D.) n = 36
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ/√n
Z = (27 - 27) / (2/√36) = 0/0.33333
Z = 0
P(Z < 0) = 0.5
