Answer:
The code to this question can be given as:
Code:
int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.
newScores = oldScores; //holds value.
for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.
{
newScores.at(i) = newScores.at(i+1); //holds value in newScores.
}
newScores.at(lastVector) = oldScores.at(0); //moving first element in last.
Explanation:
- In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
- In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
- This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
- Then we use another for loop for print newScores array elements.
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I rearranged them so the program would make sense by arranging the interaction in a logical order then placing input statements in between
In excel spreadsheets, Sidney
need to consider specifying relationships between the information you have
stored in your spreadsheets when creating formulas. The elements that will help
you understand using spreadsheet are the constants, operators, references and
functions. This will enable her to use the formulas, without hassle in
spreadsheets.
Answer:
Breaking it down I guess for me, you could take down all the possible things that you could do. Eliminating things, one by one. It could help working on a computer by not letting yourself get over-whelmed by all your programming and thinking "alright, this THEN this."
Explanation:
