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vova2212 [387]
3 years ago
10

Please help!! thanks!

Mathematics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

A.) Yes

Step-by-step explanation:

Plug in (3,2) into both equations ....

2(3) - 3(2) = 0

2(3) + 2 = 8

Then solve ....

2(3) - 3(2) = 0

6 - 6 = 0

0 = 0

2(3) + 2 = 8

6 + 2 = 8

8 = 8

Since both equation are true the solution (3,2) is true

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Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

Recall that

\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

Rewrite and expand the given limand as the product

\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

4 0
2 years ago
Can I have help please I am stuck on this question it would mean the world if u helped me have a nice day! =) &lt;3
guajiro [1.7K]

Answer:

F

Step-by-step explanation:

1m = 100cm

0.8m = 100*0.8 = 80cm

5 0
3 years ago
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