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7nadin3 [17]
3 years ago
9

What is the answer to this?

Computers and Technology
1 answer:
Anit [1.1K]3 years ago
5 0

Answer: I think the Valorous Unit Ribbon

Explanation: I don't really understand what's it asking but I sort of did to get this answer!

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You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert t
zhenek [66]

Answer:

See explaination

Explanation:

import java.io.File;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class SecretMessage {

public static void main(String[] args)throws IOException

{

File file = new File("secret.txt");

StringBuilder stringBuilder = new StringBuilder();

String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1

if(file.exists())

{

Scanner inFile = new Scanner(file);

StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file

ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem

stringBuilder = stringBuilder.append(ch);

while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.

str= line.nextToken();

numberOfTokens += 1; // Incrementing the numberOfTokens by one.

if(numberOfTokens == 5) { // Checking if it is the fifth word

ch = str.toUpperCase().charAt(0);

stringBuilder = stringBuilder.append(ch);

numberOfTokens =0;

}

}

System.out.println("----Secret Message----"+ stringBuilder);

}

}

}

5 0
3 years ago
WILL MARK BRAINLIEST HELP
hichkok12 [17]

My guess would be A.

3 0
3 years ago
Read 2 more answers
Binary is best interpreted by a computer because ​
Nookie1986 [14]
Because it is the back-end programming. It is the basis of all of the other computer languages and allows the computer to function.
8 0
3 years ago
Read 2 more answers
Write a function called play_round that simulates two people drawing cards and comparing their values. High card wins. In the ca
elena-s [515]

Answer:

Here you go, Change it however you'd like :)

Explanation:

import random as r

def play_round(p1, p2):

   cards = [1,2,3,4,5,6,7,8,9,10,"J","Q","K","A"]

   play1 = r.choice(cards)

   play2 = r.choice(cards)

   

   while play1 == play2:

       play1 = r.choice(cards)

       play2 = r.choice(cards)

   

   if cards.index(play1) > cards.index(play2):

       return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p1}"

   else:

       return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p2}"

print(play_round("Bob","Joe"))

8 0
3 years ago
Write a method swaparrayends() that swaps the first and last elements of its array parameter. ex: sortarray = {10, 20, 30, 40} b
Alexus [3.1K]
In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:

#include <stdio.h>

void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}


void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);

for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}

getchar();
}

In higher languages like C# it becomes much simpler:

        static void Main(string[] args)
        {
            int[] myArray = {1, 2, 3, 4, 5};
            swaparrayends(myArray);
            foreach (var el in myArray)
            {
                Console.Write(el + " ");
            }

            Console.ReadLine();
        }

        static void swaparrayends(int[] arr)
        {
            int temp = arr[0];
            arr[0] = arr.Last();
            arr[arr.Length - 1] = temp;
        }

3 0
3 years ago
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