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daser333 [38]
2 years ago
11

Question 5 (1 point) The line whose equation is y = 4x + 2 has a y-intercept whose coordinates are​

Mathematics
1 answer:
11111nata11111 [884]2 years ago
8 0

Answer: 2xy

Step-by-step explanation:

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Select all the correct answers. Function g is a transformation of the parent exponential function. Which statements are true abo
lesantik [10]

The correct statements are:

Function g has a y-intercept of (0,4)

The range of the function g is (3, ∞).

The function g is positive over the interval (-∞ , ∞ ).

The parent function i.e. exponential function is defined by:

y=f(x)=aˣ

From the graph given below,

1. The graph of the function g is 3 units above the graph of the parent exponential function. as the parent exponential function aˣ cuts the y-axis at (0,1) and the child transformed function cut at (0,4) for which g is 4-1=3 units above the parent function  

2. The domain of the function is set of all the inputs for which function is defined. From the graph of function g, it is clear tha the domain of the function is (-∞ , ∞ ) as the domain of the parent exponential function is also (-∞ , ∞ ).

3. The y-intercept is the point at which function cut the y-axis. Graph of function g cut the y-axis at (0, 4). Therefore, Function g has the y-intercept at (0,4).

4. From the graph it is clear that Function g increases over the interval (-∞, 0) .

5. The range of the function is the output values of the function. From the graph, it is observed that the range of function g is (3, ∞). as its minimum value is 3 then the maximum value is ∞.

6. As, the graph of function g is drawn above the x-axis. Therefore, Function g lies completely on +ve y-axis, so function g is positive over the interval (-∞ , ∞ ).

Therefore The correct statements are:

Function g has a y-intercept of (0,4)

The range of the function g is (3, ∞).

The function g is positive over the interval (-∞ , ∞ ).

Learn more about the exponential function

here: brainly.com/question/2456547

#SPJ10

5 0
2 years ago
Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) &lt; 0, csc (t) &
Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as \sin (t) \ne 0,

\displaystyle \csc t = \frac{1}{\sin t}.

Therefore, \csc(t) > 0 is equivalent to \sin (t) > 0.

Consider a unit circle centered at the origin. If the terminal side of angle t intersects the unit circle at point (x,\, y), then

  • \cos (t) = x, and
  • \sin(t) = y.

For angle t,

  • x = \cos(t) < 0, meaning that the intersection is to the left of the y-axis.
  • y = \sin(t) > 0, meaning that the intersection is above the x-axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0
3 years ago
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