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Serjik [45]
2 years ago
7

HELP PLEASE!!

Mathematics
1 answer:
Sloan [31]2 years ago
3 0

Answer:

D.) an = 4 * an-1

Step-by-step explanation:

a(n) = (1/3) * 4^(n-1)

a(n-1) = (1/3) * 4^(n-1-1) = (1/3) * 4^(n-2)

Thus,

a(n) = (1/3) * 4 * 4^(n-2) = 4 * [(1/3) * 4^(n-2)] = 4 * a(n-1), so that

a(n) = 4 * a(n-1).

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Three consecutive odd integers have a sum of 3.what are the number
lapo4ka [179]
X = smallest odd
x + 2 = second odd
x + 4 = third odd

x + x + 2 + x + 4 = 3
3x + 6 = 3
3x = -3
x = -1

The numbers are -1, 1, 3. Hope this helps!
6 0
3 years ago
Can you tell me the answer it's my birthday today
ExtremeBDS [4]
Happy birthday, and the answer would be 3m(squared). The formula is LxH/2.
3 0
3 years ago
The side of a square is 32/5, what is the area of the square
Anvisha [2.4K]

Answer: 1,024/25 or 40.96

Step-by-step explanation:

The length of one side of a square is 32/5, and all sides of a square have the same length, then all sides of the square have 32/5 as the length.

In order to get the area of the square, you need to multiply one side by another.

32/5 * 32/5 = 1,024/5 (fraction form)

32/5 = 6.4

6.4 * 6.4 = 40.96 (decimal form)

7 0
3 years ago
Mark gets picked up by the bus at 7:40 he arrives at school at 8:10 how long does it take to get to school
Elodia [21]
You could do this in two ways, you could either subtract immediately or convert the time given in hours into minutes
STEP 1:
8:10
- 7:40
which will give 0:30
STEP 2:
8 hours 10 minutes into minutes is
(8 * 60) +10 = 490 minutes
7 hours 40 minutes into minutes is
(7*40) + 40 = 460 minutes
490 - 460
= 30minutes
3 0
3 years ago
Read 2 more answers
4, Find a number x such that x = 1 mod 4, x 2 mod 7, and x 5 mod 9.
olchik [2.2K]

4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.

Start with

x=7\cdot9+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 4, the last two terms vanish and we're left with

x\equiv63\equiv64-1\equiv-1\equiv3\pmod4

We have 3^2\equiv9\equiv1\pmod4, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 7, the first and last terms vanish and we're left with

x\equiv72\equiv2\pmod7

which is what we want, so no adjustments needed here.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 9, the first two terms vanish and we're left with

x\equiv140\equiv5\pmod9

so we don't need to make any adjustments here, and we end up with x=401.

By the Chinese remainder theorem, we find that any x such that

x\equiv401\pmod{4\cdot7\cdot9}\implies x\equiv149\pmod{252}

is a solution to this system, i.e. x=149+252n for any integer n, the smallest and positive of which is 149.

3 0
2 years ago
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