HELP PLEASE!!

Mathematics

1 answer:

Sloan [31]2 years ago

3 0

Answer:

D.) an = 4 * an-1

Step-by-step explanation:

a(n) = (1/3) * 4^(n-1)

a(n-1) = (1/3) * 4^(n-1-1) = (1/3) * 4^(n-2)

Thus,

a(n) = (1/3) * 4 * 4^(n-2) = 4 * [(1/3) * 4^(n-2)] = 4 * a(n-1), so that

a(n) = 4 * a(n-1).

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Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

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$AL=\frac{40}{360}*2(3.1415)(3)$ . I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

$AL=\frac{1}{9}*2(3.1415)(3)$ which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in: