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8090 [49]
3 years ago
10

Consider the figures below. Which of the following statements are true, given <S is congruent to <J and <N is congruent

to <E? Select all that apply.
<A is congruent to <O

Triangle SAN~TriangleJOE

Triangle SAN is congruent to Triangle JOE

SN is congruent to JE

The perimeter of Triangle JOE is half the perimeter of Triangle SAN

There exists a sequence of rigid motion that maps Triangle JOE onto Triangle SAN

There exists a sequence of rigid and non-rigid motions that maps Triangle SAN onto Triangle JOE

​

Mathematics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

Just took it

Step-by-step explanation:

Dovator [93]3 years ago
6 0

Answer:

<A is congruent to <O

Triangle SAN~TriangleJoe

There exists a sequence of rigid motion that maps Triangle JOE onto Triangle SAN

Step-by-step explanation:

So sorry if i am wrong!! I hope this can help!

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Anisha invested $8,000 in an account that earns 10% interest How much money will she have in 15 years of the interest is compoun
tamaranim1 [39]

Answer:

A = $35,198.32

Step-by-step explanation:

<em>Use the formula to calculate compound interest</em>:

A = P(1 + i)ⁿ

"A" for total amount after the time period

"P" for principal, or starting money

"i" for the interest rate in a compounding period

To calculate "i":

i = r / c

"n" for the number of compounding periods

To calculate "n":

n = tc

So, we can <u>combine the formulas</u> into:

A = P(1+\frac{r}{c})^{tc}

"c" is the compounding periods in a year. (quarterly = 4)

<u>We know</u>:

P = 8000

r = 10% / 100 = 0.1

t = 15

c = 4

<u>Substitute the information in the formula</u>.

A = P(1+\frac{r}{c})^{tc}

A = 8000(1+\frac{0.1}{4})^{15*4}      Solve "i" and "n"

A = 8000(1+0.025)^{60}        Solve inside the brackets

A = 8000(1.025)^{60}         Do the exponent before multiplying by 8000

A = 35198.318             Exact answer

A ≈ 35198.32              Round to two decimal places for money

Therefore she will have $35,198.32 after 15 years.

5 0
3 years ago
7x – 2y = -5 which is the correct answer help a homie out pls
Elis [28]
Neither of those work for that equation
7 0
3 years ago
Need fast in plz help me quick
Eva8 [605]
6)x-7+10 7)3+x+1 8)8x-16 9)x/2-9
5 0
3 years ago
Read 2 more answers
1. The sum of a two-digits number is 13. The tens digit is 8 less than twice the units digit. What is the number?
alexgriva [62]

Answer:

<u>The number is 67</u>

Step-by-step explanation:

<u>Equations</u>

Let's consider the number 83. The tens digit is 8 and the unit digit is 3. Note the tens digit's addition to the number is 80, and the unit's addition is 3. This means the tens digit adds 10 times its value, that is, 83 = 8*10 + 3.

Now, let's consider the number ab, where a is the tens digit, and b is the unit digit. It follows that

Number=10*a+b

The question gives us two conditions:

1) The sum of a two-digits number is 13.

2) The tens digit is 8 less than twice the units digit.

The first condition can be expressed as:

a + b = 13                     [1]

And the second condition can be written as:

a = 2b-8                      [2]

Replacing [2] into [1], we have:

2b-8 + b = 13

Operating:

3b = 13 + 8

3b = 21

Solving for b:

b = 21 / 3 = 7

Substituting into [2]:

a = 2*(7) - 8 = 6

Thus, the number is 67

3 0
3 years ago
The table represents the observed number of leaves y on x branches of a tree. Calculate the rate of change between 3 and 4 branc
Dennis_Churaev [7]

Answer:

<h2>25</h2>

Step-by-step explanation:

The rate of change of number of tree y on x branches of a tree is expressed as shown;

m = Δy/Δx where;

m is the rate of change

Δy is the change in number of leaves  between 3 and 4

Δx is change in number of branches  between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

From table between 3 and 4, y₂ = 100, y₁ = 75, x₂ = 4, x₁ = 3

m = 100-75/4-3

m = 25/1

m = 25

<em>Hence the rate of change between 3 and 4 branches is 25</em>

5 0
3 years ago
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