4.5/y = 12.5/4 PLEASE HELP!!! SOS
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Answer:
There are significant differences among the mean tensile strengths for different temperatures.
Step-by-step explanation:
A one-way ANOVA is used to test whether there is significant difference between the means for more than two groups.
The hypothesis can be defined as follows:
<em>H₀</em>: There is no difference between the means, i.e. .
<em>Hₐ</em>: There is a significant difference between the means, i.e.at least one of the mean is different.
Use MS-Excel to perform the analysis of variance.
Go to Data → Data Analysis → Anova: Single Factor.
A dialog box will open.
Enter the data and enter Alpha as 0.05.
Press OK.
The output is attached below.
The F-value is, 8.40458.
The <em>p</em>-value of the test is, 0.00139.
Decision Rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected.
<em>p</em>-value = 0.00139 < <em>α</em> = 0.05
The null hypothesis will be rejected at 5% level of significance.
Concluding that there are differences among the mean tensile strengths for different temperatures.
