Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.
There are 30% of pure antifreeze in 3 gallons of solution, then
3 gallons - 100%,
a gallons - 30%,
where a gallons is the amount of pure antifreeze in given solution.
Mathematically,
Now in new solution there will be x+0.9 gallons of pure antefreeze.
x+3 gallons - 100%,
x+0.9 - 65%
or
Answer: he should add 3 gallons of pure antifreeze.
The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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The domain of the function in this case will be for when the denominator is different from zero:
3x ^ 2- 3 = 0
3x ^ 2 = 3
x ^ 2 = 3/3
x ^ 2 = 1
x = + / - 1
Therefore the domain of this function are all reals without including x = 1 and x = -1
Answer:
.............,...........,.......................... ans is b
Answer:
Answer:x=
−3z−1
0
Step-by-step explanation:x=
Step 1: Add -2x to both sides.
2x+3z+4+−2x=2x+3+−2x
3z+4=3
Step 2: Add -3z to both sides.
3z+4+−3z=3+−3z
4=−3z+3
Step 3: Add -4 to both sides.
4+−4=−3z+3+−4
0=−3z−1
Step 4: Divide both sides by 0.
0
0
=
−3z−1
0
x=
−3z−1
0
