we know that
diameter of the base of a cylindrical can= 4 in----------> r=2 in
h=6.5 in
[surface area]=2*[pi*r²]+[2*pi*r*h]
then
[surface area]=2*[pi*2²]+[2*pi*2*6.5]=[ 25.13 ]+[ 81.68 ]=106.81 in²
the answer is 106.8 in²
If h=4, then 5(4)+7= 27. Using PEMDAS, do multiplication first, so 20, then add the 7.
Answer:

Step-by-step explanation:

Answer: the number is -14
Step-by-step explanation: let the number be x
2(x+4) = x-6
2x+8 = x-6
2x-x = -6-8
x = -14
If the two diagonals are
and
, the are of the rhombus is

So, in your case, the area is

The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.