Combine the like terms to create an equivalent expression:<br> -n+(-4)-(-4n)+6}

HOW MANY AUTOMOBILE LICENSE PLATES CAN BE MADE IF EACH PLATE

ahrayia [7]

The number of license plates is 11232000

<h3>How to determine the number of license plates?</h3>

The given parameters are:

Characters = 6 i.e. 3 letters and 3 digits

Letters = 3 different letters

Digits = 3 different digits

There are 10 different digits and 26 different letters.

Since each character is different from the other, then we have:

Digits = 10, 9 and 8

Characters = 26, 25 and 24

The number of license plates is then calculated as:

n = 10 * 9 * 8 * 26 * 25 * 24

Evaluate the product

n = 11232000

Hence, the number of license plates is 11232000

Read more about permutation at:

brainly.com/question/11732255

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3 0

1 year ago

A $10,000 deposit at the bank will double in value in 9 years. Give a formula for the accumulated amount t years after the inves

wolverine [178]

Answer:

$S = P(1.08)^{t}$

Step-by-step explanation:

A $10,000 deposit at the bank will double in value in 9 years.

If the interest is r% and it is compounded each year, then we can write from the formula of compound interest that

$20000 = 10000(1 + \frac{r}{100})^{9}$

⇒ $2 = (1 + \frac{r}{100})^{9}$

⇒ $1 + \frac{r}{100} = 1.08$

⇒ r = 8%

Therefore, the formula for the accumulated amount t years after the investment is made will be

$S = P(1 + \frac{8}{100})^{t} = P(1.08)^{t}$

where, P is the invested principal and S is the accumulated sum. (Answer)

3 0

3 years ago

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week

Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of individuals who work at home at least once per week = $\frac{41}{250}$ = 0.164

n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<em>99% confidence interval for p</em> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ , $0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ ]

= [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0

3 years ago

if the nth term of a sequence is 2n+2n squared, find the first 3 terms and the 10th term please help

marishachu [46]

Answer:

3rd term: 24

10th term: 220

Step-by-step explanation:

2*3 + 2*(3^2) = 6 + 2*9 = 6 + 18 = 24

2*10 + 2*(10^2) = 20 + 2*100 = 20 + 200 = 220

8 0

3 years ago

Brainly is D U M B and bad

slega [8]

Thanks for the points.

7 0

2 years ago

Read 2 more answers

Combine the like terms to create an equivalent expression: -n+(-4)-(-4n)+6}