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Andre45 [30]
4 years ago
7

How would you solve 5x+3y=12 by graphing it?

Mathematics
2 answers:
Crank4 years ago
6 0
First you must get y by itself and then set it up in slope intercept form: y=mx+b where m is the slope, b is the y intercept, and y is what it equals too
lukranit [14]4 years ago
4 0
Check the picture below.

a "solution" or zero or root, is pretty much just an x-intercept, namely, what is the value of "x" when the graph touches the x-axis.  Keeping in mind that y = 0 at that moment.

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3 years ago
Identify the coordinates of the vertex of f(x) = 3x2 + 12x − 8, and identify whether it is an absolute minimum or absolute maxim
DaniilM [7]

The vertex of f(x) = 3x^2 + 12x − 8 is (2,28) absolute minimum

<h3>How to determine the vertex?</h3>

The equation is given as:

f(x) = 3x^2 + 12x − 8

Differentiate the function

f'(x) = 6x + 12

Set to 0

6x + 12 = 0


Divide through by 6

x + 2 = 0

Solve for x

x = -2

Substitute x = -2 in f(x) = 3x^2 + 12x − 8

f(2) = 3 *2^2 + 12 *2 − 8

Evaluate

f(2) = 28

This means that the vertex is (2,28)

A quadratic function is represented as:

f(x) =ax^2 + bx + c

When a is positive, then the vertex of the function is an absolute minimum.

This means that f(x) = 3x^2 + 12x − 8 has an absolute minimum vertex because 3 is positive


Read more about quadratic functions at:

brainly.com/question/18797214

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7 0
2 years ago
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