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romanna [79]
3 years ago
8

100 points and brainliest

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

you only gave 50 points but thanks haha

Step-by-step explanation:

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I need help i will mark brainiest
o-na [289]

Step-by-step explanation:

option D

16+ 125/ 6= 141/6 = 47 / 2 = 23.5

<em><u>plz </u></em><em><u>mark</u></em><em><u> my</u></em><em><u> answer</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u> plzzzz</u></em><em><u>.</u></em>

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8 0
3 years ago
Read 2 more answers
What is required for two triangles to be similar?
BartSMP [9]

Answer:

1.the corresponding angles are propositional

2.the corresponding sides are proportional

4 0
4 years ago
You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your
pochemuha
 <span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1] 

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan. 

We require B(n) = 0...i.e. balance of 0 after n months. 

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1] 

Then, with some algebraic juggling we get: 

n = -[log(1 - (Ai/P)]/log(1 + i) 

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43 

Also, i = (13.6/100)/12 => 0.136/12 per month 

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12) 

so, n = 4.15 months...i.e. 4 payments + remainder 

b) Now we have A = $754.43 - $300 = $454.43 so, 

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12) 

so, n = 1.54 months...i.e. 1 payment + remainder 
</span>
8 0
4 years ago
Y=23x+5 and<br><br> y=x+3<br><br> what is the solution
kondor19780726 [428]

Answer:

I solved this like you would a system of equations - if that is not the answer you need LMK

Point form:

(- 1/11, 32/11)

Equation Form:

x = -1/11, y = 32/11

Step-by-step explanation:

8 0
3 years ago
Solve what is 1/2 x 15
Andreas93 [3]

Answer:

7.5

Step-by-step explanation:

it's basically just 15 divided by 2

8 0
3 years ago
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