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3 years ago

A segment in the complex plane has a midpoint at −1 + 7i. If one endpoint of the segment is at

2 answers:

6 0

Consider two pairs of coordinates (x₁, y₁) and (x₂, y₂), the mid-point of these coordinates are $( \frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

We have midpoint (-1, 7i) and one pair of coordinate (3, 8i)

The other pair of coordinate would be given by
$( \frac{x_1+3}{2}= -1, \frac{y_1+8}{2} =7)$

The value of x is (2 × -1) - 3 = -2 - 3 = -5
The value of y is (2 × 7) - 8 = 14 - 8 = 6

The value of x represents the real part
The value of y represents the imaginary part

The other coordinate is (-5, 6i)

Licemer1 [7]3 years ago

5 0

Answer:

-5, 6i

Step-by-step explanation:

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3 years ago

Given the functions, f ( x ) = x - 8 and g ( x ) = x2 x - 1, perform the indicated operation. when applicable, state the domain

kondor19780726 [428]

(fg)(x)= x³ - 7x² - 9x + 8

domain is (-∞,∞)

Given: f(x)= x-8, g(x)= x² +1x - 1

To find (fg)(x) we multiply f(x) and g(x)

(fg)(x) = f(x) * g(x)

(fg)(x)= (x-8) (x²+x-1)

(fg)(x)= x³ + x² - x - 8x² - 8x +8

(fg)(x)= x³ - 7x² - 9x + 8

we know, domain for all cubic function is set of all real numbers

domain is (-∞,∞)

Know more about "functions" here: brainly.com/question/12431044

#SPJ4

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1 year ago

What is the equation of a circle whose center is at (-2, 1) and radius is 2.2?

Lena [83]

C is the correct answer

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3 years ago

What is the product?

DENIUS [597]

Answer:

14 x^5 - 21 x^4 - 266 x^3 - 315 x^2

Step-by-step explanation:

Expand the following:

7 x^2 (2 x + 5) (x^2 - 4 x - 9)

| | | | 2 x | + | 5

| | x^2 | - | 4 x | - | 9

| | | | -18 x | - | 45

| | -8 x^2 | - | 20 x | + | 0

2 x^3 | + | 5 x^2 | + | 0 | + | 0

2 x^3 | - | 3 x^2 | - | 38 x | - | 45:

7 x^2 2 x^3 - 3 x^2 - 38 x - 45

7 x^2 (2 x^3 - 3 x^2 - 38 x - 45) = 7 x^2 (2 x^3) + 7 x^2 (-3 x^2) + 7 x^2 (-38 x) + 7 x^2 (-45):

7 2 x^2 x^3 - 3 7 x^2 x^2 - 38 7 x^2 x - 45 7 x^2

7 (-45) = -315:

7 2 x^2 x^3 - 3 7 x^2 x^2 - 38 7 x^2 x + -315 x^2

7 x^2 (-38) x = 7 x^(2 + 1) (-38):

7 2 x^2 x^3 - 3 7 x^2 x^2 + -38×7 x^(2 + 1) - 315 x^2

2 + 1 = 3:

7 2 x^2 x^3 - 3 7 x^2 x^2 - 38 7 x^3 - 315 x^2

7 (-38) = -266:

7 2 x^2 x^3 - 3 7 x^2 x^2 + -266 x^3 - 315 x^2

7 x^2 (-3) x^2 = 7 x^4 (-3):

7 2 x^2 x^3 + -3×7 x^4 - 266 x^3 - 315 x^2

7 (-3) = -21:

7 2 x^2 x^3 + -21 x^4 - 266 x^3 - 315 x^2

7 x^2×2 x^3 = 7 x^(2 + 3)×2:

7×2 x^(2 + 3) - 21 x^4 - 266 x^3 - 315 x^2

2 + 3 = 5:

7 2 x^5 - 21 x^4 - 266 x^3 - 315 x^2

7×2 = 14:

Answer: 14 x^5 - 21 x^4 - 266 x^3 - 315 x^2

5 0

4 years ago