Answer:
Step-by-step explanation:
20.1metres / seconds
We want to convert to metres /minutes
It is known that 60seconds=1minutes
So therefore, either we multiply 20.1metres/seconds by
60seconds/1minutes
Or
1minutes/60seconds
Multiplying with the above does not change the magnitude of the quantity because it is like we are multiplying by 1.
Since we want to cancel seconds and it is in the denominator, so to do this we need to multiply with the fraction that has the seconds as numerator.
So, we are going to multiply with 60seconds/1minutes
20.1metres/seconds ×60seconds/minutes
1206metres/minutes.
So the correct fraction is the StartFraction 60 seconds Over 1 minute, which is the third option
Answer:
60-15/9
Step-by-step explanation:
Subtract (-) 15 from 60: 60-15
Divide (/) by 9: 60-15/9
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
60 eggs.
Step-by-step explanation:
a dozen is 12. So 5 times 12 is 60.
Answer:
<h2>If we placed the number 10 in the box, we obtain a system of equations with infinitely many solutions.</h2>
Step-by-step explanation:
The given system is
<em>It's important to know that a system with infinitely many solutions, it's a system that has the same equation</em>, that is, both equation represent the same line, or as some textbooks say, one line is on the other one, so they have inifinitely common solutions.
Having said that, the first thing we should do here is reorder the system
This way, you can compare better both equations. If you look closer, observe that the second equation is double, that is, it can be obtained by multiplying a factor of 2 to the first one, that is
So, by multiplying such factor, we obtaine the second equation. Observe that 
must be equal to 10, that way the system would have infinitely solutions.
Therefore, the answer is 10.
