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1 year ago

WILL GIVE LOTS OF POINTS HELP SOLVE SOON, NUMBER 7

Mathematics

2 answers:

Nadusha1986 [10]1 year ago

8 0

Answer: 4x + 3 = 39

Step-by-step explanation:

Because you don't know how much each pizza costs, you can write it as x.

You multiply x by 4 to get 4x and add 3 because thats how much the chips cost.

That added up should equal 39 because thats how much he spent.

OleMash [197]1 year ago

5 0

Answer: The answer is C ( 4x + 3 = 39 )

Step-by-step explanation:

4 = number of Pizzas. x = price of pizza. 3 = price of chips. 39 = total of 4 pizzas and chips together.

1) 4x + 3 = 39

2) 4x = 39 - 3

You will seperate the variable(4x) and the constants(3 and 9) So, you move (+3) to the other side making it negative. Then, you subtract (39-3) which will equal to (36)

4) 4x = 36

5) x = 36/4

You want to move the coefficient(4) to the other side. Thus, will make it a division becaue the oppisite of multiplication is division. So you cancel it out from x because 4/4 is 1.

6) x = 9

You divided 36/4 which will equal to 9

7) 4(9) + 3 = 39

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Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y

sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is $z = 7 \sin (v)$ and the interval for u is $0\le u\le 1$ .

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder $y^2+z^2 = 49$ , that lies between the places x = 0 and x = 1.

$x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?$

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

$0\le u\le 1$

Equation for z.

Replacing the given equation for the parameterization $y = 7 \cos(v)$ on the given equation for the cylinder give us

$(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49$

Solving for z, by moving $49 \cos^2 (v)$ to the other side

$z^2 = 49-49 \cos^2 (v)$

Factoring

$z^2 = 49(1- \cos^2 (v))$

So then we can apply Pythagorean Theorem:

$\sin^2(v)+\cos^2(v) =1$

And solving for sine from the theorem.

$\sin^2(v) = 1-\cos^2(v)$

Thus replacing on the exercise we get

$z^2 = 49\sin^2 (v)$

So we can take the square root of both sides and we get

$z = 7 \sin (v)$

4 0

2 years ago

Estimate the answer to 65.78 + 13.43 by first rounding each number to the nearest tenth.

gizmo_the_mogwai [7]

65.8 + 13.4 = 79 .2. So the answer is c

6 0

2 years ago

How is dividing and multiplying with an area model similar and How is it different?

MrRissso [65]

Answer:

In multiplication the numbers you multiply are called factors; the answer is called the product. In division the number being divided is the dividend, the number that divides it is the divisor, and the answer is the quotient.

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2 years ago

(- 40 + 8) x (- 6) – 24

lyudmila [28]

Answer:

168

Step-by-step explanation:

(-40+8)×(-6)-24

=(-32)×(-6)-24

=192-24

=168

7 0

2 years ago

Read 2 more answers

A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers"

Maru [420]

Answer:

Answer : D

Step-by-step explanation:

A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is â0.104 to 0.336.

Which of the following statements is correct?

A) This confidence interval is not reliable because the samples are so small.

B)This confidence interval is of no use because it contains 0, the value of no difference between classes.

C)This confidence interval is reasonable because the sample sizes are both at least 5.

D) This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.

The Answer is D - This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.

In this setup, all the students are already involved in the data. This is not a sample from a larger population, but probably, the population itself.

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2 years ago