The answer is 18.2
I got the answer by solving it
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
Solution 1: 1+1
Solution 2: 1-
Step-by-step explanation:
x^2-2=2x
x^2-2x-2=0
Use quadratic equation.
(-b+-
)/2a
(2+-
)/2
(2+-
)/2
(2+-
)/2
Solution 1: (2+2)/2=1+1
Solution 2: 1-
12) 12, 8
12 - 8 = 4
12 + 8 = 20
Answer: 4 < x <span>< 20
13) 11, 3
11 - 3 = 8
11 + 3 = 14
Answer: 8 </span>< x <span>< 14
Hope this helps :)</span>
Your answer is C cause to corresponds to it!
