Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Answer:
1st option
Step-by-step explanation:
The domain and range are all real numbers , that is
domain { x | x ∈ R }
range { y | y ∈ R }
I think it’s b not sure tho
Answer:
Option B
Step-by-step explanation:
Lets open the brackets of L.H.S.
Lets substract q² from both the sides.
Lets divide both the sides by q.
Answer: It should be 74.5875
Step-by-step explanation: If you did 0.35*55.25= you should get a number then if you add that with the discounted price, $55.25, you should get 74.5875
