If they are both albino there is no chance for them to have any other skin color because it is not in their genes. The phenotype gene is always going to be albino.
Answer:
1/3 of black F2 progeny will be homozygous.
Explanation:
Here, BB = black coat color = true breeding dominant black strain
bb = white coat color = true breeding recessive white strain
When true breeding black and white guinea pigs are mated to give F1 progeny:
BB X bb = Bb ( all black guinea pigs )
When two of the F1 guinea pigs are mated to give F2 progeny:
Bb X Bb = BB, Bb, Bb, bb
F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.
Hence, 1/3 of black F2 progeny will be homozygous.
The answer is single nucleotide polymorphisms (SNPs)
It checks for variation in nucleotide sequences in particular genes that may be different among people, especially in different races. An example is a gene for melanin that would determine the trait for skin color. Single nucleotide changes in the gene between population can be used to differentiate populations.
Answer:
neutrons, electrons, and protons
Explanation:
DNA and Vaccines work by injecting a small dosage of the virus so your immune system already knows how to react.
