Find the Solution in the Interval [0,2 pi] tan(theta/7)+ square root3= 0
1 answer:
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The solutions to the equation are ...
tan(θ/7) +√3 = 0
tan(θ/7) = -√3
θ/7 = arctan(-√3) +nπ . . . . . . . for integer n
θ = 7(-π/3 +nπ) = 7π(n -1/3)
For n=0, θ = -7π/3 -- not in the required interval.
For n=1, θ = 14π/3 -- not in the required interval.
There are no solutions in the required interval.
You might be interested in
Answer:
see the explanation
Step-by-step explanation:
Let
x ----> the smaller number
y ----> the larger number
we know that
A larger number is 2 more than 4 times a smaller number
<u><em>Identify the key words</em></u>
is (=)---> equal
more (+) ---> addition
times (*) ---> multiplication
That means
The larger number y is equal to multiply the smaller number x by 4 and then adds 2
so
----> equation A
The larger number is also 8 more than 2 times the smaller number
<u><em>Identify the key words</em></u>
is (=)---> equal
more (+) ---> addition
times (*) ---> multiplication
That means
The larger number y is equal to multiply the smaller number x by 2 and then adds 8
so
----> equation B
Solve the system of equations by substitution
equate equation A and equation B
Find the value of y
substitute the value of x in equation A or equation B
therefore
The smaller number is 3 and the larger number is 14