= 33
the n th term of an arithmetic sequence is
=
+ (n - 1 )d, hence
= 13 + (5 × 4 ) = 13 + 20 = 33
Answer:
24 would prefer CREST
6 woul NOT prefer Crest
Step-by-step explanation:
4:5=x:30
Answer: 
<u>Step-by-step explanation:</u>
(a) First, find the x-coordinates where the two equations cross
y = -1 and y = 3 - x²
-1 = 3 - x²
-4 = -x²
4 = x²
± 2 = x → These are the upper and lower limits of your integral
Then subtract the two equations and integrate with upper bound of x = 2 and lower bound of x = -2
<u />
![\int_{-2}^{+2}[(3-x^2)-(-1)]dx\\\\\\=\int_{-2}^2(4-x^2)dx\\\\\\=4x-\dfrac{x^3}{3}\bigg|_{-2}^{+2}\\\\\\=\bigg(8-\dfrac{8}{3}\bigg)-\bigg(-8+\dfrac{8}{3}\bigg)\\\\\\=\large\boxed{\dfrac{32}{3}}](https://tex.z-dn.net/?f=%5Cint_%7B-2%7D%5E%7B%2B2%7D%5B%283-x%5E2%29-%28-1%29%5Ddx%5C%5C%5C%5C%5C%5C%3D%5Cint_%7B-2%7D%5E2%284-x%5E2%29dx%5C%5C%5C%5C%5C%5C%3D4x-%5Cdfrac%7Bx%5E3%7D%7B3%7D%5Cbigg%7C_%7B-2%7D%5E%7B%2B2%7D%5C%5C%5C%5C%5C%5C%3D%5Cbigg%288-%5Cdfrac%7B8%7D%7B3%7D%5Cbigg%29-%5Cbigg%28-8%2B%5Cdfrac%7B8%7D%7B3%7D%5Cbigg%29%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B%5Cdfrac%7B32%7D%7B3%7D%7D)
(b) We know the upper and lower bounds of the y-axis as y = 3 and y = -1
Next, find the equation that we need to integrate by solving for x.
y = 3 - x²
x² + y = 3
x² = 3 - y
x 

Now, subtract the two equations and integrate with upper bound of y = 3 and lower bound of y = -1
![\int_{-1}^{+3}[(\sqrt{3-y})-(-\sqrt{3-y})]dy\\\\\\=\int_{-1}^{+3}(2\sqrt{3-y})dy\\\\\\=\dfrac{-4\sqrt{(3-y)^3}}{3}\bigg|_{-1}^{+3}\\\\\\=\bigg(0\bigg)-\bigg(-\dfrac{32}{3}\bigg)\\\\\\=\large\boxed{\dfrac{32}{3}}](https://tex.z-dn.net/?f=%5Cint_%7B-1%7D%5E%7B%2B3%7D%5B%28%5Csqrt%7B3-y%7D%29-%28-%5Csqrt%7B3-y%7D%29%5Ddy%5C%5C%5C%5C%5C%5C%3D%5Cint_%7B-1%7D%5E%7B%2B3%7D%282%5Csqrt%7B3-y%7D%29dy%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-4%5Csqrt%7B%283-y%29%5E3%7D%7D%7B3%7D%5Cbigg%7C_%7B-1%7D%5E%7B%2B3%7D%5C%5C%5C%5C%5C%5C%3D%5Cbigg%280%5Cbigg%29-%5Cbigg%28-%5Cdfrac%7B32%7D%7B3%7D%5Cbigg%29%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B%5Cdfrac%7B32%7D%7B3%7D%7D)
4 : 8
x 9 => 36 : 72 <=== equivalent
The volume of the ball is:
V = (4/3) * (pi) * (r ^ 3)
Where r is the radius.
We have then:
diameter 14 inches:
V1 = (4/3) * (pi) * ((14/2) ^ 3)
V1 = 1436.75504 in ^ 3
diameter 18 inches:
V2 = (4/3) * (pi) * ((18/2) ^ 3)
V2 = 3053.628059 in ^ 3
The volume change is:
V = V2-V1
V = 3053.628059 - 1436.75504
V = 1616.873019 in ^ 3
Answer:
The approximate change in the volume of the ball is:
V = 1616.9 in ^ 3