Answer:
this will b the anwser
Step-by-step explanation:
It helps demonstrate it since it forms a right triangle in the middle with 2 base lengths and a hypotenuse. The areas of the squares can be plugged into the pythagorean theorem in order to find the answer
Answer:
B
Step-by-step explanation:
because in the periodic table nitrogen is 7, and oxygen is 16
Answer:
Go through the explanation you should be able to solve them
Step-by-step explanation:
How do you know a difference of two square;
Let's consider the example below;
x^2 - 9 = ( x+ 3)( x-3); this is a difference of two square because 9 is a perfect square.
Let's consider another example,
2x^2 - 18
If we divide through by 2 we have:
2x^2/2 -18 /2 = x^2 - 9 ; which is a perfect square as shown above
Let's take another example;
x^6 - 64
The above expression is the same as;
(x^3)^2 -( 8)^2= (x^3 + 8) (x^3 -8); this is a difference of 2 square.
Let's take another example
a^5 - y^6 ; a^5 - (y ^3)^2
We cannot simplify a^5 as we did for y^6; hence the expression is not a perfect square
Lastly let's consider
a^4 - b^4 we can simplify it as (a^2)^2 - (b^2)^2 ; which is a perfect square because it evaluates to
(a^2 + b^2) ( a^2 - b^2)
Answer:
![\displaystyle \boxed{8[x + 2][x^2 - 2x + 4]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7B8%5Bx%20%2B%202%5D%5Bx%5E2%20-%202x%20%2B%204%5D%7D)
Step-by-step explanation:
Use the Difference of Cubes [(a³ - b³)(a² + 2ab + b²)] to figure this out:
![\displaystyle 8x^3 + 64 \\ 8[x^3 + 8] \\ \\ x + 2 = \sqrt[3]{x^3 + 8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%208x%5E3%20%2B%2064%20%5C%5C%208%5Bx%5E3%20%2B%208%5D%20%5C%5C%20%5C%5C%20x%20%2B%202%20%3D%20%5Csqrt%5B3%5D%7Bx%5E3%20%2B%208%7D)
Then, since the divisor\factor is in the form of <em>x - c</em>, use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
−2| 1 0 0 8
↓ −2 4 −8
___________
1 −2 4 0 → 
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x³ + 8]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², the −2x follows right behind it, then 4, giving you the other factor of
, attaching this to the first two factors you started out your work on:
![\displaystyle \boxed{8[x + 2][x^2 - 2x + 4]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7B8%5Bx%20%2B%202%5D%5Bx%5E2%20-%202x%20%2B%204%5D%7D)
I am joyous to assist you anytime.