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3 years ago

Choose all the pairs of lines that are parallel.

Mathematics

2 answers:

madam [21]3 years ago

8 0

Answer:

<h2>2.lineUX and lineVY</h2><h2>3.lineVY and lineWZ</h2>

amid [387]3 years ago

6 0

The answers are:

2. Line UX and line WZ
3. Line VY and line WZ

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Jane says that she can use addition to show that the graphs of 2x - 3y = 1 and 2x + 3y = 2 are intersecting lines. In two or mor

iogann1982 [59]

For this case we have the following equations:
2x - 3y = 1
2x + 3y = 2
When adding both equations we observe that:
Sentence 1: we have an equation of a variable, which in this case will be x. We can clear the value of x.
Sentence 2: Knowing the value of x, we can substitute in any equation and find the value of y.
Sentence 3: The value of x and y represents the point of intersection of both lines (x, y).

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3 years ago

Which fraction is greater than the fraction represented by the model?

babunello [35]

Answer:

7/16

Step-by-step explanation:

7/16>3/8

4 0

3 years ago

Read 2 more answers

Find the area of the composite figure below.

pashok25 [27]

Answer: D is the correct answer.

8 0

3 years ago

The quotient of a number w and(-8), which is then increased by 7

Colt1911 [192]

Okay, since quotient is the answer to a division problem, you will divide w and -8. Increased means to add so, you will +7.

w/-8 +7 is what the expression looks like.

5 0

4 years ago

1/6d + 2/3 = 1/4(d-2) how to solve

natita [175]

Greetings!

Solve for d.
$1/6d + 2/3 = 1/4(d-2)$
Distribute the Parenthesis.
$1/6d + 2/3 = 1/4*d+1/4*-2$
$1/6d + 2/3 = 1/4d+1/4*-2/1$
$1/6d + 2/3 = 1/4d-2/4$
Reduce.
$1/6d + 2/3 = 1/4d-1/2$
Add -2/3 to both sides.
$(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)$
Simplify.
$1/6d=1/4d-3/6-4/6$
$1/6d=1/4d-7/6$
Add -1/4d to both sides.
$(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)$
Simplify.
$2/12d)-3/12d=-7/6$
$-1/12d=-7/6$
Divide both sides by -1/12.
$(-1/12d)/-1/12=(-7/6)/-1/12$
Simplify.
$d=(-7/6)*-12/1$
$d=84/6$
Reduce.
$d=14/1$
$d=14$

Hope this helps.
-Benjamin

7 0

4 years ago