Question

Two cars are driving towards an intersection from perpendicular directions. The first car's velocity is 10 meters per second and the second car's velocity is 6 meters per second. At a certain instant, the first car is 4 meters from the intersection and the second car is 3 meters from the intersection. What is the rate of change of the distance between the cars at that instant (in meters per second)?

Answer 1

Answer:

use: E = P x t

Step-by-step explanation:

E = energy = J

P = power = W

t = time = s