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Semenov [28]
2 years ago
14

Ek pal eisa vi aata hei uss time vo hamse bewafa pyar karne lagti hei​

Advanced Placement (AP)
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

pyar aisa karo ki unhe hume chodne se darr lage

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(a)

We have been given an equation x^{2}=-2+y+5cosy. Upon taking derivative of this equation with respect to x on both the sides, we get:

2x=0+\frac{dy}{dx}+5(-siny)\frac{dy}{dx}\\2x=(1-5siny)\frac{dy}{dx}\Rightarrow \frac{dy}{dx}=\frac{2x}{1-5siny}

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In order to write the equation of tangent line, we need to find the slope of the line. We know that point (3,11) lies on the graph. Therefore, we write the slope of the tangent as:

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