First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:

Step-by-step explanation:
Equation of a circle:
The equation of a circle with center
and radius r is given by:

Center: (−2, −5); radius= 1
This means that
. So



This is the equation of the circle.
Answer is 13.75 inches for each side of the square board
Step by step
A square with an area of 189 in sq. , take square root of 189 = 13.75 inches
Answer:
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Answer: See Explanation
Step-by-step explanation:
This worksheet seems to be about "Special Right Triangles"
In this worksheet, it instructs you to find the missing side lengths.
Explaining number 1)
Step 1) Identifying the triangle and what it means
Since the triangle in number one is a 45-45-90 triangle with the given side length of "1" on one of the legs of the triangle, it can be concluded that the other leg also has a side length of "1" (due to the ratio of side on a 45-45-90 degree triangle), is also states the triangle has 45 degrees labeled on one of the angles, is can also be concluded that the other missing angle is 45 degrees.
Step 2) Answer
The answer to b is 1 and the answer to a is square root of 2, due to the properties of a 45 45 90 triangle (refer attachment)
*you can also use the following attachment to help you on this problem