Answer:
Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.
Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.
Step-by-step explanation:
We are given the following hypothesis below;
Let p = <u><em>proportion of people who write with their left hand</em></u>
So, Null Hypothesis, 
: p = 0.22 {means that the proportion of people who write with their left hand is equal to 0.22}
Alternate Hypothesis, 
: p 
0.22 {means that the proportion of people who write with their left hand is different from 0.22}
Now, Type I error states that we conclude that the null hypothesis is rejected when in fact the null hypothesis was actually true. Or in other words, it is the probability of rejecting a true hypothesis.
So, in our question; Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.
Type II error states that we conclude that the null hypothesis is accepted when in fact the null hypothesis was actually false. Or in other words, it is the probability of accepting a false hypothesis.
So, in our question; Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.
Answer:
C. 4.5 inches
Step-by-step explanation:
Given the following data;
Force, F = 10 pounds
Extension, e = 3 inches
First of all, we would determine the spring constant (k) using the following formula;
Force = spring constant * extension
10 = spring constant * 3
Spring constant = 10/3
Spring constant = 3.33 pounds per inches.
Next, we would find the extension of the spring when a force of 15 pounds is applied;
F = ke
15 = 3.33 * e
Extension, e = 15/3.33
Extension, e = 4.5 inches.
We will begin by grouping the x terms together and the y terms together so we can complete the square and see what we're looking at.
. Now we need to move that 36 over by adding to isolate the x and y terms.
. Now we need to complete the square on the x terms and the y terms. Can't do that, though, til the leading coefficients on the squared terms are 1's. Right now they are 9 and 4. Factor them out:
. Now let's complete the square on the x's. Our linear term is 4. Half of 4 is 2, and 2 squared is 4, so add it into the parenthesis. BUT don't forget about the 9 hanging around out front there that refuses to be forgotten. It is a multiplier. So we are really adding in is 9*4 which is 36. Half the linear term on the y's is 3. 3 squared is 9, but again, what we are really adding in is -4*9 which is -36. Putting that altogether looks like this thus far:
. The right side simplifies of course to just 36. Since we have a minus sign between those x and y terms, this is a hyperbola. The hyperbola has to be set to equal 1. So we divide by 36. At the same time we will form the perfect square binomials we created for this very purpose on the left:
. Since the 9 is the bigger of the 2 values there, and it is under the y terms, our hyperbola has a horizontal transverse axis. a^2=4 so a=2; b^2=9 so b=3. Our asymptotes have the formula for the slope of
which for us is a slope of negative and positive 3/2. Using the slope and the fact that we now know the center of the hyperbola to be (2, 3), we can solve for b and rewrite the equations of the asymptotes.
give us a b of 0 so that equation is y = 3/2x. For the negative slope, we have
which gives us a b value of 6. That equation then is y = -3/2x + 6. And there you go!
15-2x3=9 following the rule of PEMDAS
