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cluponka [151]
3 years ago
8

What is the solution to x + 12 = 25?A. x=13B. x=12C. x=37D. x=24​

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0

Answer:

x=3

Step-by-step explanation:

subtract 12 from both sides of the equation

x+12=25

x+12-12=25-12

then subtract the numbers

x=13

Archy [21]3 years ago
6 0

Answer:

A . x=13 is the solution of this question.

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List all partitions of the set. (a) (1,2) (b) [a, b,c)
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3 years ago
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Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
1. Simplify the expression below.<br> 2(x + 2) + 3(-x-7) -5 ( 2x - 4)
MrMuchimi

Answer: -11x+15

Step-by-step explanation: distributed property: 2x+2-3x-7-10x+20, -11x+15

5 0
3 years ago
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