Answer:
F) ![380\frac{4}{7}ft^2](https://tex.z-dn.net/?f=380%5Cfrac%7B4%7D%7B7%7Dft%5E2)
Step-by-step explanation:
<u>Find the area of each part</u>
Area of right triangle: ![A=\frac{1}{2}bh=\frac{1}{2}(6)(18)=(3)(18)=54ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7Dbh%3D%5Cfrac%7B1%7D%7B2%7D%286%29%2818%29%3D%283%29%2818%29%3D54ft%5E2)
Area of rectangle: ![A=bh=(12)(18)=216ft^2](https://tex.z-dn.net/?f=A%3Dbh%3D%2812%29%2818%29%3D216ft%5E2)
Area of left triangle:
(this is because both triangles are congruent)
Area of semicircle: ![A=\frac{1}{2}\pi r^2=\frac{1}{2}(\frac{22}{7})(\frac{12}{2})^2=\frac{22}{14}(6)^2=\frac{11}{7}(36)=56\frac{4}{7}ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%3D%5Cfrac%7B1%7D%7B2%7D%28%5Cfrac%7B22%7D%7B7%7D%29%28%5Cfrac%7B12%7D%7B2%7D%29%5E2%3D%5Cfrac%7B22%7D%7B14%7D%286%29%5E2%3D%5Cfrac%7B11%7D%7B7%7D%2836%29%3D56%5Cfrac%7B4%7D%7B7%7Dft%5E2)
<u>Add up all the areas</u>
<u />![A=54ft^2+216ft^2+54ft^2+56\frac{4}{7}ft^2=380\frac{4}{7}ft^2](https://tex.z-dn.net/?f=A%3D54ft%5E2%2B216ft%5E2%2B54ft%5E2%2B56%5Cfrac%7B4%7D%7B7%7Dft%5E2%3D380%5Cfrac%7B4%7D%7B7%7Dft%5E2)
Answer:
c. $3866
Step-by-step explanation:
Put 8 where n is and do the arithmetic.
A(8) = $3300(1.02^8) = $3386
It depends on where each train its heading is both trains destination is 600 miles apart from each other then, Train A is going 70mph so divide 600 by 70 to get 8.57 round it up to get 8.58 then multiply by 70 to get 600.4 round down to get 600. Train B is going 80mph so divide 600 by 80 to get 7.5 then multiply by 80 to get 600. The trains should be 600 mi apart by 1 hour and 14 minutes.
Combine like terms to get 2x + 6x which is 8x and 3y + 9y which is 12y so the simplified answer is 8x + 12y