Answer:
22.143
Step-by-step explanation:
49.419-27.276=22.143
Answer:
DIABETES
Step-by-step explanation:
= 1 1/2 ÷ 2 / 3
= 3 / 2 ÷ 2 / 3
= 3 / 2 · 3 / 2
= 9 / 4
2.5 / 1 is your anwer : )
Answer:
x = - 5, x = - 11
Step-by-step explanation:
Given
y = 
The denominator cannot be zero as this would make y undefined.
Equating the denominator to zero and solving gives the values that x cannot be, that is
(x + 5)(x + 11) = 0
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
x + 11 = 0 ⇒ x = - 11
Thus
x = - 11 and x = - 5 are excluded values.
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
