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Keith_Richards [23]
3 years ago
6

Look at the question, please orginize it in a good manner. NO LINKS!

Mathematics
2 answers:
tia_tia [17]3 years ago
3 0

Answer:

for the first one its       right 2 down 5

for the second one its       right 5 down 2

for the third one its          left 2 up 5

i hope this helps pls tell me if im wrong

elixir [45]3 years ago
3 0

1) right 2 down 5

2) right 5 down 2

3) left 2 up 5

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Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

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y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

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\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

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Step-by-step explanation:

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Step-by-step explanation:

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