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3 years ago

Look at the question, please orginize it in a good manner. NO LINKS!

Mathematics

2 answers:

tia_tia [17]3 years ago

3 0

Answer:

for the first one its right 2 down 5

for the second one its right 5 down 2

for the third one its left 2 up 5

i hope this helps pls tell me if im wrong

elixir [45]3 years ago

3 0

1) right 2 down 5

2) right 5 down 2

3) left 2 up 5

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A ladder 40 feet in length rests against a vertical wall. The foot of the ladder is 7 feet from the wall. What angle, θ, does th

Pachacha [2.7K]

The ladder makes 79.92 degrees of angle with the ground (Calculation: Cos A = 7/40 = 0.175 resulting A = ACos 0.175 = 79.92 degrees). This problem can be solved by using a simple trigonometry formula of Cosine which stated Cos A = Adjacent/Hypotenuse. The ladder length of 40 feet is the hypotenuse side of the triangle and the 7 feet distance between the ladder's foot and the wall is the adjacent side.

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3 years ago

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Laine reads 25 pages in 30 minutes. If Laine reads 200 pages at this same rate, how long will it take her?

irinina [24]

Well think about it

50 pages = 1 hour (60 mins)

so it would take laine 4 hours in total to read 200 pages at the rate

hope that helps :)

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3 years ago

The polynomial equation x^3+x^2=-9x-9 has complex roots +/-3i What is the other root? Use a graphing calculator and a system of

Ierofanga [76]

For this case what you can do is factorize the polynomial equation, which would be left like follows
x ^ 3 + x ^ 2 + 9x + 9 = 0
(x + 1) (x ^ 2 + 9) = 0
Resolving, we have that the missing root is
x = -1
Answer
x=-1

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3 years ago

a high school stage collapsed in Fullerton, California, when 250 students got on stage for the finale of a musical production. T

Lera25 [3.4K]

Answer:

Step-by-step explanation:

In this question, the important information we get from this is that the stage can support 12,750 students. We are asked, if the average weight of a student is 140 pounds, what is the maximum number of students that can be on the stage safely?

To solve, we simply divide 12,750 by 140.

$x=\frac{12,750}{140}$

$x= 91.07$

We get 91.07 as our answer. Since we are considering the maximum number of students, then we must round 91.07 to the nearest whole number which would be 91.

The maximum number of students who could safely be on the stage is 91.

6 0

3 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago