Solve for x. 3(x + 2) = 12 2 X = 4 3 1 x = 3 3 O x = 2 x = 6
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Probability that no zebras collide is 0.25
The zebras are represented as z1, z2 and z3.
Z1 to B, Z2 to C, and Z3 to A come first
Following that, z1 to C, z2 to A, and z3 to B =
Consequently, the likelihood of no collision is 2×1/8 = 0.25.
<h3>What are the types of probability distributions ?</h3>Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.
- The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
- The likelihood of a sure or certain event is one.
- The likelihood of an impossibility is 0 (0).
- Every event has a probability between 0 and 1.
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