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kenny6666 [7]
2 years ago
14

Given 2 and 1 over 10 times negative seven times 5 over 12, determine the product.

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
4 0

The solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

<h3>How to Multiply Fractions?</h3>

2 and 1 over 10 times negative seven times 5 over 12 can also be expressed as; 2¹/₁₀ * ⁽⁻⁷ * ⁵⁾/₁₂

Multiplying out the bracket gives;

²¹/₁₀ * -³⁵/₁₂

Dividing by common factors gives;

= ⁷/₂ *  ⁻⁷/₄

= -49/8

= -6¹/₈

This can also be written as negative six and 1 over 8

Thus, we conclude that the solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

Read more about Multiplication of fractions at; brainly.com/question/7335118

#SPJ1

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Answer:

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Step-by-step explanation:

1) Notation and definitions

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

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In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

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