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adell [148]
3 years ago
8

What is this i tried doing it but i just dont get it at all 7.5 + n + 9.63.

Biology
2 answers:
Arte-miy333 [17]3 years ago
5 0

Answer:

+17.13

Explanation:

<em>brainliest please</em>

e-lub [12.9K]3 years ago
5 0

Solving?

Answer:

n+17.13

Explanation:

Add the numbers

7.5+n+9.63

17.13+n

Rearrange terms

17.13+n

n+17.13

Solution

n+17.13

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Solve the scrambled letter according to the clue: nlpituloo _ _ _ _ _ _ _ _ _: Litter on the ground or harmful chemicals in the
tia_tia [17]

Answer:

pollution

Explanation:

The correct word would be pollution.

<em>Pollution can be described as the presence of ecologically harmful substances in the environment. </em>

Littering the ground is considered pollution because it is harmful to the environment in the long term. Harmful chemical in water is outrightly considered pollution because this will hurt the organisms living in the water and rendered the water unusable to those around it.

8 0
3 years ago
Read 2 more answers
Positive feedback is a control system that sends a signal to ________ a response.
vlada-n [284]

Answer:

increase

Explanation:

hope this helps :)

8 0
3 years ago
PLZ HURRY IT'S URGENT!
Anna71 [15]

Answer:

C.  Fe2O3 + 2Al → 2Fe + Al2O3

7 0
3 years ago
What is most likely the cause of this difference from the rest of the population
vekshin1

Answer:

Gene mutation is most likely the cause of this difference from the rest of the population. Log in for more information.

Explanation:

CAN I GET BRAINLIEST

5 0
3 years ago
Congenital analgesia is a rare autosomal recessive trait. What is the likelihood that the first two offspring of a cross between
telo118 [61]

The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16

<h2>Autosomal Recessive Traits</h2>

For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.

In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.

            Bb    x    Bb

          BB   Bb   Bb   bb

Probability of producing unaffected offspring = 3/4

Probability of producing affected offspring = 1/4

Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia

    = 1/4 x 1/4

        = 1/16

More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults

6 0
3 years ago
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