Answer:
The cell address of 4th row and 4th column is
4D/D4
Answer:
1. 2588672 bits
2. 4308992 bits
3. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Explanation:
1. Number of bits in the first cache
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits
2. Number of bits in the Cache with 16 word blocks
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits
3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num2 < num1:
print("Second integer can't be less than the first.")
else:
for i in range(num1,num2+1,5):
print(i,end=" ")
Explanation:
This gets the first integer from the user
num1 = int(input())
This gets the second integer from the user
num2 = int(input())
If the second is less than the first, the following prompt is printed
<em>if num2 < num1:</em>
<em> print("Second integer can't be less than the first.")</em>
If otherwise, the number between the intervals is printed with an increment of 5
<em>else:</em>
<em> for i in range(num1,num2+1,5):</em>
<em> print(i,end=" ")</em>
<em />
<span>He would click on the Test 1 column and press Sort, then click on the Test 2 column and press Sort.
It depends on what you learn because it says "shift"</span>
Keyboard would be the correct answer
