First you need to find out how much Molly paid. So, $24 times 0.25 equals $6 off so $24 minus $6 equals $18. Molly paid $18 for the jeans. Then to find the percentage of increase you would find the difference between how much the store bought the jeans minus how much they sold them for which is $18-$6=$12 then u would do $12 divided by $6 which is 2 and then multiply by 100 to get 200%. So the store earned a 200% increase on the jeans they sold to Molly.
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
The rectangular coordinates of the point are (3/2 , √3/2)
Step-by-step explanation:
* Lets study how to change from polar form to rectangular coordinates
- To convert from polar form (r , Ф) to rectangular coordinates (x , y)
use these rules
# x = r cos Ф
# y = r sin Ф
* Now lets solve the problem
∵ The point in the rectangular coordinates is (√3 , π/6)
∴ r = √3 and Ф = π/6
- Lets find the x-coordinates
∵ x = r cos Ф
∵ r = √3
∵ Ф = π/6
∴ x = √3 cos π/6
∵ cos π/6 = √3/2
∴ x = √3 (√3/2) = 3/2
* The x-coordinate of the point is 3/2
- Lets find the y-coordinates
∵ y = r sin Ф
∵ r = √3
∵ Ф = π/6
∴ y = √3 sin π/6
∵ sin π/6 = 1/2
∴ y = √3 (1/2) = √3/2
* The y-coordinate of the point is √3/2
∴ The rectangular coordinates of the point are (3/2 , √3/2)
Answer:
54.75 = 26 + x
Step-by-step explanation:
You can solve for x by subtracting 26 from both sides of the equation.
Answer:
<em>b = 50√c</em>
Step-by-step explanation:
If b varies directly as the square root of c, this is expressed as;
b∝√c
b = k√c
k is the constant of proportionality
Given b = 100 and c = 4
100 = k√4
100 = 2k
k = 100/2
k = 50
Substitute k = 50 into the original expression:
Recall that: b = k√c
b = 50√c
<em>hence equation that can be used to find other combinations of b and c is b = 50√c</em>
