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pentagon [3]
2 years ago
7

Please help me with this homework

Mathematics
1 answer:
andriy [413]2 years ago
8 0

Answer:

wow. at this point just guess

Step-by-step explanation:

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Which set of ordered pairs represents a function?
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The answer is B because it is a function
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Chris is a college student who can work a maximum of 40 hours per week. He needs to make at least $900 in order to cover his exp
IgorC [24]
Equation 1: x + y = 40 ; therefore y = 40 - x
Equation 2: 25x + 15y = 900
Find x first:

25x + 15 (40 - x) = 900
25x + 600 - 15x = 900
10x = 900 - 600
x = 300÷10
x = 30 hours Chris needs to spend for tutoring job

y = 40 - 30
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3 years ago
Find the value of x - 5x+4 + 8x-71
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Let's simplify step-by-step.

x−5x+4+8x−71

=x+−5x+4+8x+−71

Combine Like Terms:

=x+−5x+4+8x+−71

=(x+−5x+8x)+(4+−71)

=4x+−67

Answer:

=4x−67

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3 years ago
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Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

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3 years ago
If xy = 0, what must be true about either x or y?
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Answer:

One of them must be zero.

Step-by-step explanation:

For something to equal zero it needs to be multiplied by a value of zero.

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