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3 years ago

WORTH 10 points. What is the answer. True or False?

Mathematics

2 answers:

jeyben [28]3 years ago

7 0

I believe its "True"

Sveta_85 [38]3 years ago

5 0

I believe the answer is true.

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This is a variation acitivity:

sergey [27]

$\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{\underline{I} varies jointly with \underline{P} and \underline{t}}}{I=kPt} \\\\\\ \textit{we also know that } \begin{cases} P=2000\\ t=4\\ I=320 \end{cases}\implies 320=k(2000)(4)\implies \cfrac{320}{(2000)(4)} \\\\\\ 0.04=k\qquad therefore\qquad \boxed{I=0.04Pt} \\\\\\ \textit{if P=5000 and t=7, what is \underline{I}?}\qquad I=0.04(5000)(7)\implies I=1400$

8 0

3 years ago

I really need help with this

BabaBlast [244]

Answer:

A (-4, 1)
B (2, 5)

Step-by-step explanation:

The current endpoints are ...

V = (-9, 2)

W = (-3, 6)

Put each of these in the translation formula to see where the image points are.

(x, y) ⇒ (x+5, y-1)

(-9, 2) ⇒ (-9+5), 2-1) = (-4, 1) . . . . point V ⇒ V'

(-3, 6) ⇒ (-3+5, 6-1) = (2, 5) . . . . . point W ⇒ W'

The new end points are (-4, 1) and (2, 5), matching choices A and B.

7 0

3 years ago

Rationalise:<br>(1) 4/(2+root3+root7)<br>(2) 4/(2root3+root5)

Temka [501]

$\frac{4}{2+\sqrt3+\sqrt7}\cdot\frac{2-(\sqrt3+\sqrt7)}{2-(\sqrt3+\sqrt7)}=\frac{8-4\sqrt3-4\sqrt7}{2^2-(\sqrt3+\sqrt7)^2}=\frac{8-4\sqrt3-4\sqrt7}{4-3-2\sqrt{3\cdot7}-7}\\\\=\frac{8-4\sqrt3-4\sqrt7}{-6-2\sqrt{21}}=\frac{-2(2\sqrt3+2\sqrt7-4)}{-2(3+\sqrt{21})}=\frac{2\sqrt3+2\sqrt7-4}{3+\sqrt{21}}\cdot\frac{3-\sqrt{21}}{3-\sqrt{21}}\\\\=\frac{6\sqrt3-2\sqrt{63}+6\sqrt7-2\sqrt{147}-12+4\sqrt{21}}{3^2-(\sqrt{21})^2}=\frac{6\sqrt3-2\sqrt{9\cdot7}+6\sqrt7-2\sqrt{49\cdot3}-12+4\sqrt{21}}{9-21}$

$=\frac{6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4\sqrt{21}}{-12}=\frac{-8\sqrt3+4\sqrt{21}-12}{-12}=\frac{-4(2\sqrt3-\sqrt{21}+3)}{-12}\\\\=\frac{2\sqrt3-\sqrt{21}+3}{3}$

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$\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}$

4 0

4 years ago

Read 2 more answers

Write a multiplication equation that shows the denominator of 3/4 and 1/2 are related

allsm [11]

4838 4839 riel is the sender 59394

5 0

3 years ago

The relationship between the number of pounds (lb) of peppers and the

Svetlanka [38]

<h3>Answer: 3 dollars per pound</h3>

Explanation:

The unit price is the price of 1 unit, in this case one pound. So we locate x = 1 on the x axis, draw a vertical line upward til we get to the diagonal line, and then draw a horizontal line until we reach the y axis. You should arrive at y = 3.

3 0

3 years ago