Question

Find the zeros of polynomial x^2-3

Answer 1

Answer:

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Answer 2

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The required zeroes are ~

$\boxed{ \boxed {\sqrt{3}} \: \: and \: \: \boxed{- \sqrt{3} }}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's equate the given polynomial with 0, to find its roots ~

that is ~

• ${x}^{2} - 3 = 0$

• ${x}^{2} - ( \sqrt{3} ) {}^{2} = 0$

• $(x + \sqrt{3} )(x - \sqrt{3} ) = 0$

there are two cases,

Case # 1 - when (x + √3) = 0

• $x + \sqrt{3} = 0$

• $x = - \sqrt{3}$

and

Case # 2 - when (x - √3) = 0

• $x - \sqrt{3} = 0$

• $x = \sqrt{3}$