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Mademuasel [1]
3 years ago
15

Consider the transformations of a rectangle ABCD to produce a rectangle DEFG. Which sequence of Transformations results in recta

ngles that are similar but not congruent​

Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer:

A.

Step-by-step explanation:

Rotations preserve shape <u>and</u> size, but a dilation with a factor of 3, no matter where in the sequence of transformations it is, results in a shape 3 times larger.  So rotation followed by the dilation will end up being a rectangle similar to the original but 3 times its size.

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What is equivalent to the following expression select all that apply.
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C.6 3 becaue im trying to get point dont lissten to me

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Decide if the following is a true or false statement - explain how you know
Sophie [7]

Answer:

False

Step-by-step explanation:

The equation equals -1/2 - 4.25 which is -4.75, which is negative.

Hope that helps!

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3 years ago
Order of operations 5-2(5-27)+5
Artist 52 [7]

<em>The answer to your question would be 54</em>

<em />

<em>Work Shown:</em>

<em />

<em>5-2(5-27+5</em>

<em>Calculate with parenthesis (5-27): -22</em>

<em>5-2(-22)+5</em>

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3 0
2 years ago
Find the area of the shaded region. The radius of the large circle is 10 m. Round answer to the nearest hundredth.
vivado [14]

Answer:

hello the figure related to your question is missing attached below is the missing figure

answer : 157.08 m^2

Step-by-step explanation:

Calculate the area of the shaded area

= Area of the large circle - Areas of the small circles

= (( \frac{\pi }{4} ) * D^2) - 2(  ( \frac{\pi }{4} ) * d^2 )     given that the small circles are congruent

= (( \frac{\pi }{4} ) * 20^2 ) - 2 ( ( \frac{\pi }{4} ) * 10^2 )

= 314.16 - 157.08

= 157.08 m^2

8 0
3 years ago
A top-loading washing machine has a cylindrical basket that rotates about a vertical axis. The basket of one such machine starts
damaskus [11]

Answer:

n_{tot}=44rev

Step-by-step explanation:

In order to solve this problem we can make use of the following formula:

\theta=(\frac{\omega_{f}+\omega_{0}}{2})t

where θ is the total angle the basket has turned, ω is the angular velocity and t is the time.

Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

n=(\frac{f_{f}+f_{0}}{2})t

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

n=(\frac{4rev/s+0}{2})(9s)=18rev

and now let's analyze the second stage, where it decelerates, so we get:

n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev

So now that we know how many revolutions the cylindrical basket will take as it accelerates and as it decelerates we can add them to get:

n=18rev+26rev=44rev

So the basket will turn a total of 44 revolutions during this 22s interval.

3 0
3 years ago
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